injector size help.... math check plz
Read the manual to see if your question is answered there before posting. Many users will not reply if the answer is already available in the manual.
If your question is about troubleshooting, configuration, or tuning, you MUST include your processor type (MS-I or MS-II) and code version in your post. If your question is about PCB assembly or modifications, you must also include the main board version number (1.01, 2.2 or 3.0).
If you have questions about MS1/Extra or MS2/Extra code configuration or tuning, please post them at www.msextra.com Such questions posted here will be moved to: a temporary MSextra sub-forum, where they will be removed after 7 days
The full forum rules are here: Forum Rules, be sure to read them all regularly.
injector size help.... math check plz
So my engine is a 78 mopar 360 LA bored .40 over...so really a 365 ci.
Installed flat top hyp. pistons, comp cam, heads were port and polished by the owner before me (how much and how good i have no idea?), running msd 6al box, blocker hugger headers. Compression is around 10:1
Now I am not sure on the amount of HP i am making but lets just say around 300?
I want to run a tbi setup. If my math is correct I need the bore size to be 43mm with 80lb injecotrs. But to factor in the 80% cycle i would need 100lb.
I know the stock 350 came with a 43mm bore and 55# injectors.
now for the math:
355ci x 5,000 rpm / 2
= 912,500 x .80 ( the 80% is the VE airflow since you never get 100% air)
=730,000 ci / 1728 cf
= 423 cfm
stated in another post someone said they had a 4 barrel tbi that was 9.6 and it would flow 900cfm.
9.6in / 900cfm = x / 420
420 x 9.6 / 900 = x
4032 / 900 = x
x = 4.48in
4.48 / 2 = 2.24in (dividing by 2 since that is how many bores i have)
2.24 = 3.14r^2
sqr root .71 = r^2
.84 x 2
=1.7in = 43.18mm
thats for the airflow, now for the injector rating:
i figured its 25,200 F^3 per hour
.075 lbs/ft^3 is the weight of air
.075 lb/ft^3 x 25,200 F^3/hr
.075 x 25,200
1,890 lb/hr
so we will round to 1,900 to make things easier.
since we are running a 12:1 air:fuel ratio
1,900 / 2
= 158 / 2
= 79.1 lbs/hr injector
Does this seem correct???
-
- Site Admin
- Posts: 102
- Joined: Mon Feb 16, 2004 3:15 pm
- Location: San Clemente, California, USA
- Contact:

Easy way: Guess ultimate HP, say its 200. Guess a reasonably high BSFC (Brake Specific Fuel Consumption), say 0.5 lb/HP (0.55 or 0.6 might be better, but 0.5 is easy to do in my head). Multiply them 200 * 0.5 = 100 lb total fuel required to make 200 HP. Divide by number of injectors and you've got approximate injector size...
Eric