12v switched IAC... but FIdle is ground switching?
Posted: Sun Jun 20, 2010 10:11 am
Forgive me because my electrical terminology is lacking... but here we go.
I have a 3 wire PWM IAC. My strategy was to use a 33ohm 75w resistor to jump the closed wire to ground and actuate it with the FIdle_out to the open wire.
My stock ECU sends 1-12v waveform to either open or closed pin on the 3 wire PWM
But the megasquirt diagrams show FIdle_out as grounding the sensor.
Is there an easy way around this?
Here was my idea:
1) jump the 'open' wire on my IAC to 12v with the big resistor
2) hook FIdle_out to the 'close' wire on my IAC
3) hook the third wire on the IAC (was grounded) to 12v
The idea being it reverses the direction of each "open" and "close" wires, so I reverse the function of each.
Does that make sense?
I have a 3 wire PWM IAC. My strategy was to use a 33ohm 75w resistor to jump the closed wire to ground and actuate it with the FIdle_out to the open wire.
My stock ECU sends 1-12v waveform to either open or closed pin on the 3 wire PWM
But the megasquirt diagrams show FIdle_out as grounding the sensor.
Is there an easy way around this?
Here was my idea:
1) jump the 'open' wire on my IAC to 12v with the big resistor
2) hook FIdle_out to the 'close' wire on my IAC
3) hook the third wire on the IAC (was grounded) to 12v
The idea being it reverses the direction of each "open" and "close" wires, so I reverse the function of each.
Does that make sense?